Consider the following reaction. The structur | vedclass

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(C) The reaction involves the addition of a Grignard reagent to a nitrile. $1$. The reaction of benzonitrile $(C_6H_5CN)$ with phenylmagnesium bromide

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Triphenylmethanol

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(C) The reaction involves the addition of a Grignard reagent to a nitrile. $1$. The reaction of benzonitrile $(C_6H_5CN)$ with phenylmagnesium bromide $(C_6H_5MgBr)$ in excess,followed by hydrolysis,proceeds as follows: $2$. First,the nucleophilic phenyl group from $C_6H_5MgBr$ attacks the electrophilic carbon of the nitrile group $(C \equiv N)$ to form an imine salt intermediate: $C_6H_5-C(C_6H_5)=NMgBr$. $3$. Since the Grignard reagent is in excess,it can further react with the imine or the resulting ketone. However,in the standard reaction of nitriles with excess Grignard reagents followed by hydrolysis,the intermediate imine is hydrolyzed to a ketone. $4$. Wait,let us re-evaluate: The reaction of a nitrile with one equivalent of Grignard reagent gives an imine,which upon hydrolysis yields a ketone. If the Grignard reagent is in excess,the ketone formed can react further with another equivalent of the Grignard reagent to form a tertiary alcohol after hydrolysis. $5$. Benzonitrile + $C_6H_5MgBr$ (excess) $\rightarrow$ Intermediate $\xrightarrow{H_3O^+}$ $C_6H_5-C(OH)(C_6H_5)_2$ (Triphenylmethanol). $6$. Therefore,the main product is Triphenylmethanol.

Consider the following reaction. The structure of the main product will be

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